Question

There are two spheres of radius r1 and r2 the sum of these radius is 10cm and the sum of there volume is 880cm3 then find the product when these two radius are multiplied

Answer 1

Dear friend,

The answer is given in the attachment. I hope it helps you!

Answer 2

Answer:

Step-by-step explanation:

See guys it's a simple question :-

Now ,it's given that r1+r2=10cm

Volume of sphere+volume sphere

of radius r1 of radius r2. =880

=4/3π(r1)^3. + 4/3π(r2) ^3=880

=4/3π{(r1)^3+(r2)^3}=880

=π{(r1)^3+(r2)^3}=880*3/4

=(r1)^3+(r2)^3=220*3*7/22 (π=22/7)

=(r1)^3+(r2)^3=210 -------1

Now we know that,

(a+b)^2=a^2+b^2+2ab

(r1+r2)^2=(r1)^2+(r2)^2+2(r1)(r2)

(10)^2=(r1)^2+(r2)^2+2(r1)(r2)

100-2(r1)(r2)=(r1)^2+(r2)^2 -––––2

Now,

(r1)^3+(r2)^3=(r1){(r1)^2+(r2)^2-(r1)(r2)}

From 1 and 2

210=(10){100-2(r1)(r2)-(r1)(r2)}

21=100-3(r1)(r2)

-79= -3(r1)(r2)

79/3=(r1)(r2)