Question

There are two squares S1 and S2. The ratio of their areas is 4:25. If the side of the square S1 is 6cm, what is the length of side of S2?

Answer 1

let area of square S1 = a²
let area of square S2= b²
ratio will be a²/b²= 4:25
a/b = √4/√25
a/b = 2/5
given a= 6cm
then 6/b = 2/5
b= 30/2 = 15cm

Answer 2

Step-by-step explanation:

Given, u=20m/s

t

1

=5s

t

2

=8s

Graph: (Refer to Image)

(1) Distance travelled in first 5 sec= area of ABDE= 20×s=80m

(2) Distance travelled after the brakes are applied (area of BCD)=

2

1

×8×5=20m

(3) Total distance travelled= AreaofABCDE+AreaofBCD=80+20=100m

(4) Acceleration during the first 5 sec= 0, because uniform velocity.

(5) Acceleration during the last 8 sec= v=0,u=20m/s,t=8sec

⇒v=u+at⇒0=20+a(8)

⇒a=−2.5m/s

2

(slope of the line DC