Question

There are two squares S1 and S2. The ratio of their areas is 4:25. If the side of the square S1 is 6cm, what is the length of side of S2?

Answer 1

Area of S1= 6²= 36 sq.cm

Let, area of S2 be x
Area of S2= x² sq.cm.

$ratio = \frac{area \: of \: s1}{area \: of \: s2} = \frac{36}{ {x}^{2} }$
$\frac{4}{5} = \frac{36}{ {x}^{2} } \\ 4 \times {x}^{2} = 25 \times 36 \\ 4 \times {x}^{2} = 900$
${x}^{2} = \frac{900}{4} \\ {x}^{2} = 225 \\ x = \sqrt{225} \\ x = 15$
Hence, S2 = 15 cm

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Answer 2

Answer:

hope it helps you

Step-by-step explanation:

area of s1 = 4

area of s2= 25

$(6) ^{2} \times 4$

$x ^{2} \times 25 \: \: \: \: \: \: by \: cross \: multiply \:$

and remove 6's power so it was 36 because 6×6 = 36

$36 \times 25 \\ - - - - - \\ 4$

if you divide 36 by 4 so its 9

and 9 × 25 = 225

therefore, you will take primefacorization of 225

so it was 15 and it's your answer

= 15 answer

note = I was also attach prime factorization and solution of the question