There are two vessels containing 2 mixture of acid having different concentration. a contains 8 lt acid and b contains 6 lt acid. 2x lt was taken out from vessel a and x lt of mixture was taken out from vessel b and are poured into each other and their concentation becomes equal. find the value of x.
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Answered by
32
According to question
Acid in Container A = A = 8 lt
Acid in Container B = B = 6 lt
when 2x is taken out of Container A
Amount of acid left in A = A' = 8 - 2x
Similarly
Amount of Acid left in B = B' = 6 -x
New amount in A = a = 8 - 2x + x = 8 - x
New amount in B = b = 6 - x + 2x = 6 + x
Thus 8 - x = 6 + x
2 = 2x
x = 1
Acid in Container A = A = 8 lt
Acid in Container B = B = 6 lt
when 2x is taken out of Container A
Amount of acid left in A = A' = 8 - 2x
Similarly
Amount of Acid left in B = B' = 6 -x
New amount in A = a = 8 - 2x + x = 8 - x
New amount in B = b = 6 - x + 2x = 6 + x
Thus 8 - x = 6 + x
2 = 2x
x = 1
Answered by
9
According to Ostwald Dilution Law or Law of Ionic Equilibrium,
Degree of dissociation (α) is directly proportional to the square root of volume (√V)
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