Question

There consecutive integerers
are such that when they are
taken in increasing order and
multiplied by 2, 3 and 4 respectively
theybadd up to 74.find these numbers.and please please follow me I will follow you back​

Answer 1

So , Integers are 7, 8 , 9.

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Answer 2

$\huge\mathfrak\red {Answer:}$

Let's assume the consecutive integers as x, (x+1), (x+2).

If they are multiplied by 2, 3 and 4 respectively and the sum is 74, Then,

2x + 3(x+1) + 4(x+2) = 74

→ 2x + 3x + 3 + 4x + 8 = 74

→ 9x + 11 = 74

→ 9x = 74 - 11

→ 9x = 63

→ x = 63/9

→ x = 7

That gives us the value of numbers as

x = 7

(x+1) = 7+1 = 8

(x+2) = 7+2 = 9

$\mathfrak\purple {Hope\: this\: helps\: you...}$