there exist a tower near the house of shankar. the top of the tower a&b styled with steel wire and on the ground it is tied with string support vande Shankar try to measure the longest of the wire AC using Pythagoras theorem
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Given : BC = 60 , AB = 80
To Find : AC
Area of ΔABC
Solution:
Applying Pythagoras theorem
AC² = AB² + BC²
=> AC² = 60² + 80²
=> AC² = 3600 + 6400
=> AC² = 10000
=> AC² = 100²
=> AC = 100 ft
Area of ΔABC = (1/2) AB * BC
= (1/2) 60 (80)
= 2400 sq ft
PC = √20² + 15² = 25 ft
length of hypotenuse in ΔABC = 100 ft
Area of Δ POC = (1/2) * 20 * 15
= 150 sq ft
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