write the following cubes in expanded from:(3/2x+1)^3
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Answered by
27
Answer:
(i) (2x+1)3=(2x)3+(1)3−3(2x)(1)(2x+1)
=8x3+1+6x(2x+1)=8x3+12x2+6x+1
(ii) (2a−3b)3=(2a)3−(3b)3+3(2a)(3b)(2a−3b)
=8a3+27b3−18ab(2a−3b)=8a3−27b3−36a2b+54ab2
(iii) (23x+1)3=(23)x3+(1)3+3(23x)(1)(23x+1)
=827x3
Answered by
1
Answer:
(3/2x+1)³=27/8x³+1+9/2(3/2+1)=27/8x³+27/4x²+9/2x+1
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