Question

There is 180ml of water in a
glass and 20ml of lemon. We
want to create lemon water
such that 20% of the solution
is lemon. How many ml of
lemon would you add?​

Answer 1

Answer:

We need 20% of the solution to be lemon.

Let the amount of lemon(in ml) required be 'x'

So,

x/(x +180) = 20/100

[I added x in the denominator because solution includes solute as well]

100x = 20(x + 180)

100x = 20x + 180

80x = 180

x = 180/80

= 2.25ml

I tried my best, hope you found it helpful...

Answer 2

Given : 180 ml  of water in a glass and 20 ml of lemon we want to create lemon water such that 20% of the solution is lemon .

To find :   how many ml of lemon would we add.

Solution:

Let say x ml of lemon is added

then lemon = 20  + x  ml

Water = 180 ml

Total solution = 180 + 20 + x  =  200 +  x  ml

Lemon  % is 20 % in solution

=> 100 *   (20 + x) / ( 200 + x)   =    20  

=> => 5 *   (20 + x) = 200 + x

=> 100 + 5x = 200 + x

=> 4x = 100

=> x  = 25

25 ml of lemon will be added to get 20% of the solution

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