there is 90% water in a watermelon . what will be the amount of water in 25 kg watermelon ?
Answers
Answer:
The original weight of the watermelon is 111.11 kg.
Step-by-step explanation:
Given : A watermelon contains 90% water. If 10 kg. water evaporates then a new watermelon is formed having 80% water.
To find : The weight of original watermelon ?
Solution :
Let the original weight of watermelon is 'x' kg.
A watermelon contains 90% water and formed into 80%.
The change in percentage is 10%.
10 kg water evaporates then a new watermelon is formed.
According to question,
10=10\%\times 90\%\text{ of }x10=10%×90% of x
10=0.1\times 0.9\times x10=0.1×0.9×x
x=\frac{10}{0.1\times 0.9}x=0.1×0.910
x=111.11x=111.11
The original weight of the watermelon is 111.11 kg.
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Lossper=
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