Question

There is a 5digit no. 3 pairs of sum is eleven each. Last digit is 3 times the first one. 3 rd digit is 3 less than the second.4 th digit is 4 more than the second one. Find the digit.​

Answer 1

Answer:

The statement that "3 pairs of sum is eleven each is ambiguous.  cannot solve this. Explanation is given below.

Step-by-step explanation:

The number = a b c d e.

e = 3 a.   SInce the digits are between 0 and 9, and a is not equal to 0,

e is not equal to 0.

So   a = 1, 2 or 3.... and e = 3, 6 or 9.

So   (a, e) = (1, 3) or (2, 6) or (3, 9).

Given also

c = b - 3.  or,  b = c + 3.

and,  d = b + 4.

So  b can be 3, 4 , or 5 only.

and Hence, c can be 0, 1, or 2 only.

Hence d can be 7, 8 or 9 only.

So (b, c, d) =  (3, 0, 7) or (4, 1, 8) or (5, 2, 9).

 

Do not understand this statement that "3 pairs of sum is eleven each." ??

It is not making a good sense.

Answer 2

Explanation:

the require number be d1d2d3d4d5 Given d5=3d1 d3=d2-3 d4=d2+4 since sum of pair of digits=11 consider d3+d4=11 d2-3+d2+4=11 => d2=5 d3=d2-3 d3=5-3 d3=2  d4=d2+4=5+4 d4=9 hence require number = __529__ here 9+2=11 now we have think of a number which should be added to five to get 11 5+6=11 hence the last number is 6 since d5=3d1 ∴d1=2 hence the ans is 25296