There is a circular park of radius 4m.There is path around the park. If the radius of the outer circle is 4m,What is the width the path
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radius of outer circle =4m (R)
and radius of inner circle=r
so, width of path =22/7×(R2-r2)
=22/7×(4sq-r2)
=22/7(16-r2)
in question the radius of inner circle is not given. hence the answer is in this form. if you know the value of r then you can simply put the value of r and will get the answer.
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