Math, asked by prishasharma6219, 11 months ago

There is a conical tent in which 10 persons can stand. each person need 6m2 to stand and 60m3 air to breath. what is the height of tent?

Answers

Answered by santy2
14

The total area occupied by the 10 people is :

= 6 × 10 = 60m²

This is the base area of the cone.

The total volume of air within the conical tent is :

= 60 × 10 = 600 m³

This is the volume of the conical tent.

Formulae for the volume of a cone is :

V = 1/3 × base area × height

600 = 1/3 × 60 × H

600 = 20H

H = 600/20 = 30

The height of the tent is 30m.


Answered by manojkumar17ee511
3

Answer:

Step-by-step explanation:

Solution-Amount of area reqd.

by 1 person to stand = 6 sq.metre Amount of area reqd.

by 10 person to stand = 6x10 sq.metre

i.e 60 sq.metre So, Base Area,

pi*r*r=60 =>r*r = 60/pi ---------------(1) Now,  

Volume of air reqd.

to breathe 1 person= 60 cu.metre Volume of air reqd.

by 10 person to breathe = 60x10=600 cu.metre

So, Volume, 1/3*pi*r*r*h = 600 ---------------------(2)

Putting the value of eqn 1 in eqn 2, we get 1/3*pi*60/pi*h = 600 ==> 1/3*60*h = 600 ==> 20*h = 600 ==> h = 600/20 = 30 Therefore height = 30 metres  

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