Question

there is a driver Sunil and he is driving his car in he suddenly starts to move in opposite direction at an acceleration of 6 metre per second square and he was that acceleration and retardation in about 2 minutes and their the road was about hundred metre and a Child was standing at the end of the road about 30 metres so what will be the initial velocity and what will be the distance that the ka covered before stopping​

Answer 1

The answer might 26m

Answer 2

Explanation:

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Given,

Speed=20m/s,d=50m,retardation=5m/s

2

Let the ppossible reaction time be t

s

So the car moves 20tm And applied breaks with retardation 5m/s

2

So, the total distance under retardation is ≤50m

Thus the distance under the application of retardation =

2×5

20

2

−0

2

=s

′

⇒s

′

=40m

Therefore, 20t

s

+40≤=50⇒20t

s

≤50−40⇒20t

s

=10⇒t

s

≤

2

1

≤0.5s