there is a heap of blocks.anil makes separate heaps of 28 blocks from the same heap.nitin makes separate heaps of 42 blocks.each of them finds that 5 blocks are left after making the separate heaps. what is the smallest possible number of blocks in the heap.
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Answered by
5
28p + 5 = 32q + 5 = 42r + 5 = Total blocks
=> 28p = 32q = 42r = Total blocks - 5
Lets find out LCM of 28 , 32 & 42
28 = 2 * 2 * 7
32 = 2 * 2 * 2 * 2 * 2
42 = 2 * 3 * 7
LCM = 2 * 2 * 2 * 2 * 2 * 3 * 7 = 672
672 = total Blocks - 5
=> Total Blocks = 677
smallest possible number of blocks in the heap = 677
Answered by
5
Answer: 677
Step-by-step explanation:
The required number of blocks = (LCM of 28, 32, 42) + 5.
LCM = 672
Total blocks = 672 + 5
= 677
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