Math, asked by Pratikcwanshi2008, 9 hours ago

There is a narrow rectangular plot in the mahuli village . The perimeter of plot is in the ratio of 11x:4x . Find the cost of painting the plot at the rate of 100 m2 , if the total cost is 75000 Rs . ​

Answers

Answered by ajithasundar377
0

Answer:

Let the length of the rectangular plot be 11x and breadth be 4x.

Rate of fencing per meter = ₹100

Total cost of fencing = ₹75000

Perimeter of the plot = 2(l+b) = 2(11x + 4x) = 2×15x = 30x

Total amount

of fencing = (30x × 100)

According to the question,

(30x × 100) = 75000

⇒ 3000x = 75000

\Rightarrow x=\frac{75000}{3000}⇒x=

3000

75000

⇒ x = 25

Length of the plot = 11x = 11×25 = 275m

Breadth of the plot = 4x = 4×25 = 100m

Similar questions