Math, asked by bekeshsingh4561, 8 months ago

THERE IS A NUMBER WHOSE ONES DIGIT IS 3 TIMES MORE THAN TENS DIGIT AND SUM OF DIGITS IS AND DIFFERENCE IS 4 FIND THE NUMBER

Answers

Answered by aryastuti2005
0

Answer:

Let the tens digit number be x

Ones digit number is 3x

Difference between the two number is 4

So,

3x - x = 4

2x = 4

x = 4/2

x = 2

3x = 6

The original number = 62

Step-by-step explanation:

Hope it helps you.....

Similar questions