Question

There is a path 4m wide around a circular park of radius 50m. the diameter of the outer circle is?

Answer 1

So here, width of the path is = 4m
And the radius of the inner circle is = 50m

So the radius of the outer circle will be = 50m + 4m
=54m

Since diameter is 2 times the radius:
So diameter of the outer circle is=
54 + 54
= 108m

Answer 2

Given,

The width of the path = 4m.

Circular park radius= 50m.

To Find,

The diameter of the outer circle.

Solution,

Given that,

The outer path's width = 4m

Circular park's radius = 50m.

Outer circle's radius =

Inner circle radius + width of the path

50+4 = 54cm

The diameter of the circle will be double the radius.

Therefore, the outer circle diameter of the park

2*r = 2 * 54

d = 108m.

The diameter of the outer circle of the circular park is 108m.