Three men A, B and C complete the work in 10,13 and
12 days of A, B and c starts work together. After
2 days A left the work and next after 2 days c left the work
Then find how
many
days the whole work complete
Answers
Answer:
Step-by-step explanation:
Lcm of 10,12,15 = 60 , total work is 60 units
Efficiency of A is 60/10= 6
Efficiency of B is 60/12 = 5
Efficiency of C is 60/15 = 4
Work=time * efficiency
Work done by A,B,C in 2days = (6+5+4)*2=30 units
Remaining work =60–30= 30 units
Time taken by C to do remaining work = 30/4= 7(1/2) days
Total time take = 2+7(1/2) = 9(1/2) days
Answer:
4 (3 / 20) days
Step-by-step explanation:
A completes the work in 10 days
work in 1 day = 1/10
B completes the work in 13 days
work in 1 day = 1/13
C completes the work in 12 days
work in 1 day = 1/12
let the total work be 1
they work together for 2 days = (1/10 + 1/13 + 1/12) * 2
= (203/780) * 2
= 203/390
this the the work they did in 2 days
now the remaining the work is = total work - completed work
= 1 - (203 / 390)
= 187 / 390
now A left.
now B and C worked together for 2 days = 1/13 + 1/12
=25/156
they did this much work in another 2 days after A left.
Now C left.
the remaining work has to be done by B.
remaining work is = (187 / 390) - (25 / 156)
= (347 / 780) - (125 / 780)
= 249 / 780
so these are the total days taken to complete the work.
(249 / 780) / (1 / 13)
= (249 / 780) * (13 / 1)
= 249 / 60
= 83 /20
= 4 (3/ 20) days
Hope it helps
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