Question

There is a positive integer'X'which has digit at highest place as 6.If digit at highest place (which is 6) is dropped we get another positive integer'y'such that (x)/(y)=25 then sum of digits of least value of x is equal to ______


that's maths question
​

Answer 1

Step-by-step explanation:

pls subscribe my sister's channel it's a humble request i will follow and mark brainest &

thnx also if you will subscribe

Channel Name - Dance with divyanshi , subscribers -115

pls subscribe and upload screen shot I will follow

screenshot is mandatory

I will know if you will subscribe

font think that you will not subscribe and I will follow

pls

x=10

Answer 2

Answer: 13

Step-by-step explanation:

let us assume integer y has 'a' digits in it.

y = _ _ _ _ _ .......  (a no. of digits) a ∈ (2,3,4,5.........∞)

therefore,  

x = 6 × $10^{a}$ + y .........(1)

Given,

x/y = 25

∴ x = 25y  ........ (2)

from equation 1 and 2

25y = 6 × $10^{a}$ + y

⇒ 25y - y =  6 × $10^{a}$

⇒ 24y =  6 × $10^{a}$

⇒4y =   $10^{a}$

here,   $10^{a}$  is a multiple of 10 and a ≠ 1 . since it is not a 1 digit number.

∴   $10^{a}$ ∈ (100,1000,10000..........)

⇒y =   $10^{a}$ /4

least number belonging to   $10^{a}$ is 100

∴ y = 100/4

y = 25

from, x = 6 × $10^{a}$ + y

∴ x = 625

sum of digits in x is 6+2+5 = 13

Ans = 13

#SPJ2