Math, asked by jnvaishagupta, 1 month ago

There is a rectangular park of length 55

m and breadth 42 m in a JNV. It has small

flower beds in the shape of Trapezium,

Square, Triangle and circle in it as shown in

the figure. The dimensions of these flower

beds are also given. Vidyalaya has planted

Variety of flowers in these flower beds to

beautify it. The figure is given belowAnswer the following question :

(i) Which flower bed has more area

Triangle or square ?​

Answers

Answered by anshatt
0

Answer:

bahi muje bhi iska answer cahiye

Step-by-step explanation:

hamari jnv valo ki futti kismat

akar apko iska answer mile to bata na

Answered by RvChaudharY50
4

Answer i) :-

→ Area of ∆ = (1/2) * Base * height = (1/2) * 2 * 3.5 = 3.5 m².

→ Area of square = (side)² = (2.5)² = 6.25 m².

therefore, Square bed has more area than triangle.

Answer ii) :-

→ Area of circle = πr² = (22/7) * 2.1 * 2.1 = 22 * 0.3 * 2.1 = 13.86m².

→ Area of trapezium = (1/2)(sum of parallel sides) * height = (1/2) * (2 + 3) * 1.5 = (1/2) * 5 * 1.5 = 2.5 * 1.5 = 3.75 m².

since ,

→ 3.5 < 3.75 < 6.25 < 13.86 .

→ ∆ < trapezium < square < circle .

therefore, triangular flower bed has least area.

Answer iii) :-

→ Perimeter of vidyalaya park = 2(L + B) = 2(55 + 42) = 2 * 97 = 194 m (Ans.)

Answer iv) :-

→ Cost of planting Jasmine flower in circular flower bed = Rate / m² * Area of circular flower bed = 8 * 13.86 = Rs.110.88 (Ans.)

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