Question

there is a rectangular Park whose length and breadth are 80 metre and 60 metre respectively and another square Park whose each side is hundred metre find the perimeter of both the park and write whose perimeter greater than how much​

Answer 1

Answer:

Perimeter of square = 4  

×

Side

Area of square = Side  

×

Side = (Side)2

Perimeter of Rectangle = 2  

×

(Length + Breadth)

Area of Rectangle = Length  

×

Breadth

Step-by-step explanation:

Answer 2

Answer:

Solution : let the share of A = Rs x

And share of B = Rs(x + 70)

And share of C = Rs (x + 70 +80)= Rs ( x + 150)

Total Amount = Rs 640

X + x + 70 + x + 150 = 640

3x + 220 = 640

3x = 640 – 220

3x = 420

X = 420/3

X = 140

Hence share of A = Rs.140

And share of B = Rs .140 + 70 = Rs.210