x² (y-z) + y^2(Z-x) + z² (x-y)
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f (x²/yz) + (y²/zx) + (z²/xy) = 3
=> x³/xyz + y³/xyz + z³/xyz = 3
=> (x³ + y³ + z³)/xyz = 3
=> x³ + y³ + z³ = 3xyz
we know, when a + b + c = 0 then , a³ + b³ + c³ = 3abc
here, x³ + y³ + z³ = 3xyz then, x + y + z = 0
so, (x + y + z)³ = (0)³ = 0
hence, (x + y + z)³ = 0
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