Question

there is a regular bus service between towns A and B with bus living town A and B every 30 minutes cyclist moving with a speed of 20 kilometre per hour in a direction abey notices that a bus goes past him every 18 and its in direction of his and every 6 minut in the opposite direction what is the period of bus service​

Answer 1

Answer:

Explanation:

Let the speed of each bus = v km/h

The distance between the nearest buses plying on either car = vT km...(i)

For buses going from town A to B:

Relative speed of bus in the direction of motion of man = (v - 20)

Buses plying in this direction go past the cyclist after every 18 min. Therefore, separation between the buses

= (v - 20)×(18/60)

From (i), (v - 20)×(18/60) = vT     ...(ii)

For buses coming from B to A:

The relative velocity of bus with respect to man = (v + 20) Buses coming from town B past'the cyclist after every 6 min,

∴ (v + 20)×(6/60) = vT     ...(iii)

Solving (ii) and (iii), we get\

v = 40 km/h and T = 2/30 h

Answer 2

Explanation:

Let the speed of each bus = v km/h

The distance between the nearest buses plying on either car = vT km...(i)

For buses going from town A to B:

Relative speed of bus in the direction of motion of man = (v - 20)

Buses plying in this direction go past the cyclist after every 18 min. Therefore, separation between the buses

= (v - 20)×(18/60)

From (i), (v - 20)×(18/60) = vT     ...(ii)

For buses coming from B to A:

The relative velocity of bus with respect to man = (v + 20) Buses coming from town B past'the cyclist after every 6 min,

∴ (v + 20)×(6/60) = vT     ...(iii)

Solving (ii) and (iii), we get\

v = 40 km/h and T = 2/30 h