Math, asked by chandrashekharkumar2, 1 year ago

there is a some water in a cylindrical vessel of diameter 11 CM if an iron cube of Edge 5.5 cm is entirely immersed in the water .what is the rise in the height of water is in the vessel

Answers

Answered by destroyer1654

d=11cm

r=5.5cm

by phytagorean buoyancy principle

if an object is immersed in a fluid.fluid displaced by it is equal to its volume.

destroyer1654: if we add volume of cube=(edge)cube

destroyer1654: 5.5÷5.5×5.5

destroyer1654: sorry it is 5.5×5.5×5.5

destroyer1654: 167.38cmcube

destroyer1654: thus total volume=950.33+167.38=1116.71

destroyer1654: thus now v=πrsquareh=1116=71

destroyer1654: thus h=1116=71/π××r

destroyer1654: h=11.75 cm

destroyer1654: thus water displaced is of height 11.75-10=1=75cn

destroyer1654: mark my answer brainliest please

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