Question

there is a trapezium whose parallel sides are 8 cm and 22.3 cm and the distance between the parallel side is 3.7 cm and a rhombus with diagonals 41.8 cm and 3 cm find which figure has greater area and by how much​

Answer 1

Step-by-step explanation:

Area of Trapezium= 1/2(8+22.3)×3.7

=56.055cm^2

Area of rhombus=1/2×41.8×3

=62.7cm^2

So area of Trapezium is greater than area of rhombus

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Answer 2

Answer:

Area of trapezium=1/2Sum of parallel sides × Distance between them

= 1/2×(8+22.3)×3.7

=1/2×30.3×3.7

=15.15×3.7

=56.055cm^2

Area of rhombus=1/2× product of diagonals

=1/2×41.8×3

=1/2×125.4

=62.7cm^2

Therefore area of rhombus is greater.