There is an element which triplicates in every hour. Each of these 3 items in turn reproduce exactly 3 other items. If a single compound is kept in a container at noon and the container is full by midnight. At what time is the container 1/3 full.
Answers
Answered by
54
Hey.
Here is the answer.
The single compound is put at noon...1200hrs(0)
So, at 1300 hrs (1) no. of items = 3 =3^1
so, at 1400 hrs (2) no. of items =9 =3^2
so, at 1500 hrs (3) no. of items = 27 =3^3 ....so on...
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hence at midnight 2400 hrs (12) , no. of items = 3^12 which makes the container full.
So, 1/3 rd of 3^12= 1/3×3^12= 3^11
Hence, the container will be 1/3rd full at 2300 hrs (11) just before midnight.
Thanks.
Here is the answer.
The single compound is put at noon...1200hrs(0)
So, at 1300 hrs (1) no. of items = 3 =3^1
so, at 1400 hrs (2) no. of items =9 =3^2
so, at 1500 hrs (3) no. of items = 27 =3^3 ....so on...
.
.
.
hence at midnight 2400 hrs (12) , no. of items = 3^12 which makes the container full.
So, 1/3 rd of 3^12= 1/3×3^12= 3^11
Hence, the container will be 1/3rd full at 2300 hrs (11) just before midnight.
Thanks.
Answered by
1
Answer:
1st hour 3, 2nd hour 3^2, so on total 12 hrs. So in 12 hrs 3^12. 1/3rd of this is clearly 3^11. So ans is 11 hrs
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