Question

There was a solution of “Heaven Hill” and water in the ratio 7:9. The solution is boiled for 17/2 minutes so as to obtain the concentration of “Heaven Hill” and water in the ratio 5:4. If water evaporates at twice the rate as compared to “Heaven Hill”, find the time taken for the concentration to become 1:1 from the very initial stage in which the ratio of “Heaven Hill” and water is 7:9.

Answer 1

Answer:

6 Mins Ratio become 1:1

Step-by-step explanation:

solution of “Heaven Hill” and water in the ratio 7:9

Heaven Hill = 7 H

Water = 9H

Let say Evaporation rate of Heaven Hill =  2E per min

Then Eavporation rate of Water = 4E  per min

After 17/2 mins  

Heaven hill = 7H - 17E   & water = 9H - 34E

(7H - 17E)/(9H - 34E)  = 5/4

=> 28H - 68E  = 45H - 170E

=> 17H = 102E

=> H = 6E

Let say after T mins ratio becomes  1: 1

7H - 2TE  = 9H - 4TE

2H = 2TE

=> H = TE

H = 6E

=> 6E = TE

=> T = 6

Hence in 6 Mins Ratio become 1:1