there were 7 thifes they stole diamonds from a shop and went in jungle at next morning one of them wake up and wake all of them and said that we can divide all the diamond s among themselves . when divide among 2one dimond remain then they divide into 6 then also there remain 1 then they divide into 7 then all diamonds finish .then how may diamonds was there
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i think 0
as all the diamonds finished
hope it helps....
plz mark me as brainliest
as all the diamonds finished
hope it helps....
plz mark me as brainliest
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Let the no. Of diamonds be a
If counted in 2's one will remain such that for natural no. q, a= 2q+1
Similarly;
For natural no. p
a= 6p+1
For natural no. f
a= 7f+0
As in every case values taken are 2,6,7 so find a multiple of 7 such that every condition is satisfied. So by taking LCM we get no. Of diamonds is 42
LCM(2,6,7)= 42
If counted in 2's one will remain such that for natural no. q, a= 2q+1
Similarly;
For natural no. p
a= 6p+1
For natural no. f
a= 7f+0
As in every case values taken are 2,6,7 so find a multiple of 7 such that every condition is satisfied. So by taking LCM we get no. Of diamonds is 42
LCM(2,6,7)= 42
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