There were 80,000 voters in one constituency. One candidate out of two candidates got 60% of the votes cast. If 80% of the total votes are cast, then how many votes did the other candidate get?
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Answer:
21600
Step-by-step explanation:
Total no. of votes cast = (80÷100)80000
=64000
Votes cast for first candidate = (60÷100)64000
=38400
∴ The votes cast for the other candidate = 64000-38400
=21600.
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