There were live pieces of cloth of lengths 15 m.
1 m. 36 m, 42 m, 48 m. But all of them could
se measured in whole units of a measuring rod.
what could be the largest length of the rod?
Answers
Answer:
Once you get rid of the extraneous details, this question is asking for a common factor of each of these numbers. The way I would go about this is start with fifteen and try out each of its factors and take it from there. As it only has four (1, 15, 3, & 5) it was quite an easy process. I would start at the largest factor but it was obvious 5 could not be the answer so I began with three.
15/3=5
21/3=7
36/3=12
42/3= 14
48/3=16
All of these are whole numbers, all of these are factors of the previous numbers, any larger number could not work, the rod is 3m.This should take a person all of about ten seconds to figure out at most. This is merely explaining the exact process.
To be honest a reasonably intelligent second grader could have figured this out so I am led to question why the asker questioned this in the first place.