Question

there were three packs on special offer 1. ten grapes and five strawberry and 70 save rs 10 2. ten strawberry and ten apricot : rs 140 save rs 40 3. thirty grapes: rs 100 (save rs 20) . what would be the ful price of one grape and one strawberry and one apricot at normal price number special offers

Answer 1

Let s = strawberry

a = Apricot

g = Grapes.

Pack One's equation:

10g + 5s = 70 (offer)

10g + 5s = (70+10) {normal price}

Pack Two's equation :

10s + 10a = 140 (offer price)

10s + 10a = (140+40) {Normal price}

Pack Three's equation :

30g = 100 (offer price)

30g = 100 + 20 (Normal price)


We can get the value of g at normal price.

30g = 120

g = 120/30 = 4rs

Normal price of strawberry from pack one is :

10 × 4 + 5b = 80

5b = 80 - 40

5b = 40

b = 8

Normal price of Apricots from pack 3

10 × 8 + 10a = 180

10a = 180 - 80

10a = 100

a = 10rs

NORMAL PROCESS FOR EACH :

Grapes = Rs 4

Strawberry = Rs 8

Apricot = Rs 10