Question

Therefore, 2011
OB = OC
So, O is the mid-point of BC.
EXERCISE 7.1
I an
and
1. In quadrilateral ACBD,
AC = AD and AB bisects' LA
(see Fig. 7.16). Show that A ABCEA ABD
What can you say about BC and BD!
ACE AD
A CABELBAP
AB=AB
Saz
BC BD​

Answer 1

Answer:

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Answer 2

Question :-

In quadrilateral ACBD, AC = AD and AB bisects ∠ A (see figure). Show that ∆ABC ≅ ∆ABD. What can you say about BC and BD?

Answer :-

In quadrilateral ACBD, we have AC = AD and AB being the bisector of ∠A.

Now, In ∆ABC and ∆ABD,

AC = AD (Given)

∠ CAB = ∠ DAB ( AB bisects ∠ CAB)

and AB = AB (Common)

∴ ∆ ABC ≅ ∆ABD (By SAS congruence axiom)

∴ BC = BD (By CPCT)

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