Question

#TheRockingGirl

Answer this.

Find the weight of a body at a height equal to the radius of earth. The weight of a body at the surface of the Earth is 200 Newton.

Thanks!

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Answer 1

Answer:

50N

Explanation:

g1=g/(1+h/R)2

g1=g/4

new weight mg/4=200/4=50

Answer 2

SOLUTION

the weight of a person on the earth surface is

(w1)=m×go

where ...m=the weight of the body

go=gravitational acceleration on the surface of the earth

now on the earth surface .......

go=GM/R²

and .....

the gravitational acceleration at a height of R from the earth surface is

gR=GM/(R+R)²=GM/4R²

now the weight of the body at height of R from the surface of earth is (w2)=m×(gR)

now .....

we/w1

=mgo/mgR

=(GMm/4R²)×(R²/GMm)

=1/4

$\frac{w2}{w1} = \frac{1}{4} \\ = > w2 = \frac{1}{4} \times w1 \\ = > w2 = \frac{1 }{4} \times 200 \\ = > w2 = 50 \: \: newton$