Question

These are the first four terms of a
sequence. 27 33 39 45
Find the nth term of this sequence.

Answer 1

Step-by-step explanation:

Given:-

The first four terms of a sequence are 27 ,33 ,39, 45

To find:-

Find the nth term of this sequence.

Solution:-

Given that

The first four terms of a sequence are 27 ,33 ,39, 45

First term =27

Common difference = 33-27 = 6

d = 39-33 = 6

d = 45-39=6

Since the common difference is same throughout the sequence.

So it is an Arithmetic Progression.

We know that

The nth term of the Arithmetic Progression is

tn = a+(n-1)d

=>tn = 27+(n-1)(6)

=>tn = 27+6n-6

=>tn=21+6n

=>tn = 6n+21

Answer:-

nth term of the given sequence is 6n + 21

Used formula:-

nth term of an AP is tn = a+(n-1)d

Where, a is the first term

d is the common difference

n is the number of terms

tn is the nth or general term of the AP