These problems are very difficult for me please solve them. Thanks
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Given : Two Triangles with angle bisector and one triangle with parallel line
To find : Value of Z , a & EF
Solution:
Q 16 - Apply angle bisector formula
hence YX/YV = XW/WV
=> 13/52 = 10/Z
=> Z = 40
Similalry in Q 17
15/a = 25/(24 - a)
=> 360 - 15a = 25a
=> 40a = 360
=> a = 9
100/320 = 80/EF
=> EF = 256
EF = 256
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