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1. a+b= (a²+b²)/ab
a²b+ab²=a²+b²
a²(b-1)+b²(a-1)=0
Since a and b are positive integers
So their sqaures cannot be
negative or zero.
Therefore b-1=0 and a-1= 0
So b=1 and a= 1
Hence a²+b²= 2
Answered by
4
1. a+b= (a²+b²)/ab
a²b+ab²=a²+b²
a²(b-1)+b²(a-1)=0
Since a and b are positive integers
So their sqaures cannot be
negative or zero.
Therefore b-1=0 and a-1= 0
So b=1 and a= 1
Hence a²+b²= 2
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