Thesis contains 100 misprints distributed randomly throughout its 100 pages. What is the probability that a page observed at random contains at least two misprints
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probability that a page observed at random contains at least two misprints = 0.264
Step-by-step explanation:
Thesis contains 100 misprints distributed randomly throughout its 100 pages
In 100 pages 100 mistakes hence λ=1
probability that a page observed at random contains at least two misprints
= 1 - ( P(0) + P(1) )
P(X=x)= e^(−λ) * (λ)ˣ / x!
P(0) + P(1)
= e⁻¹ * 1⁰/0! + e⁻¹ * 1¹/1!
= e⁻¹ + e⁻¹
= 2e⁻¹
= 2/e
= 2 * 0.368
= 0.736
1 - ( P(0) + P(1) )
= 1 - 0.736
= 0.264
probability that a page observed at random contains at least two misprints = 0.264
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