Question

ABCD is a trapezium in which AB is gparallel to DC. M and N are the mid-points of AD and BC respectively. if AB = 12 cm, MN = 14 cm, then CD =

Answer 1

MN is parallel to both AB and CD. Now join AC which cuts MN at point E.

Using midpoint theorem ME=1/2(DC) and EN=1/2(AB)

MN =ME+EN=1/2(AB + CD)

CD=16 cm

Answer 2

Answer: The value of CD is 16 units.

Step-by-step explanation:

Since we have given that

AB = 12 cm

MN = 14 cm, where, M and N are the midpoints of AD and BC respectively.

We need to find the value of CD.

As we know that

$MN=\dfrac{AB+CD}{2}\\\\14=\dfrac{12+CD}{2}\\\\28=12+CD\\\\28-12=CD\\\\16=CD$

Hence, the value of CD is 16 units.