Question

thickness of a wooden box,open at the top is 1.5 cm.Its external lenght is 1.06m breath is 93 cm and internal volume is 0.6489m3 . Determine the external height of box.

Answer 1

Answer:

0.73 m

Step-by-step explanation:

Thickness of wood = 1.5 cm = $\frac{1.5}{100}=0.015 m$

External length = 1.06 m

External Breadth = 93 cm =  $\frac{93}{100}=0. 93 m$

Internal length = 1.06 m-(0.015+0.015)m = 1.03 m

Internal breadth =0.93 m-(0.015+0.015)m = 0.9 m

Let the internal height be h

Volume of wooden box = $Length \times Breadth \times Height$

                                       = $1.03 \times 0.9 \times h$

Since we are given that  internal volume is 0.6489 cubic m

So, $1.03 \times 0.9 \times h =0.6489$

$h =\frac{0.6489}{1.03 \times 0.9}$

$h =0.7$

so, Internal height is 0.7 m

So, external height = 0.7 m+0.015 m+0.015 m = 0.73 m

Hence the external height of box. is 0.73 m