Question

third proportional to (x^2 - y^2) and (x-y) is? ​

Answer 1

Answer:

(x - y)/(x + y).

Step-by-step explanation:

Let the third proportional to (x² - y²) and (x - y) be P.

Therefore, (x² - y²), (x - y) and P are in proportion.

=> (x² - y²) : (x - y) = (x - y) : P

=> (x² - y²)/(x - y) = (x - y)/P

=> P = (x - y)²/(x² - y²)

=> P = (x - y)(x - y)/(x + y)(x - y)

=> P = (x - y)/(x + y).

Therefore, the third proportional to (x² - y²) and (x - y) is (x - y)/(x + y).

Answer 2

(⊙_⊙;) Well, the question having third is confusing, it should be 4th lol but well,

Answer:

(x - y) / (x + y)

Step-by-step explanation:

Let the third proportional to (x² - y²) and (x - y) be Z.

Therefore, (x² - y²), (x - y) and Z are in proportion.

=> (x² - y²) : (x - y) = (x - y) : Z

=> (x² - y²)/(x - y) = (x - y)/Z

Z= (x - y)²/(x² - y²)

Z= (x - y)(x - y)/(x + y)(x - y)

Z = (x - y)/(x + y).

SO it is  (x - y)/(x + y).

¯\_(ツ)_/¯ sImPlE aS tHaT