third question in the above
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Yes
Because a circle is circumscribed a quadrilateral
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In ∆POQ and ROS
PO=RO{radius of circle}
QO=OS{radius of circle}
angle POQ=angleROS{vertically oppositeangle}
So, By Cong. rule SAS ∆POQ~∆ROS.
PQ=RS. { By CPCT}
PO=RO{radius of circle}
QO=OS{radius of circle}
angle POQ=angleROS{vertically oppositeangle}
So, By Cong. rule SAS ∆POQ~∆ROS.
PQ=RS. { By CPCT}
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