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the roots of ax^2+x+1=0 , where A not equal to zero , are in the ratio 1 : 1. Then a is equal to :
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hi mate,
Answer: Here, ax^2+x+1=0 ; a not equal to 0
as we know relation b/w coefficient of quadratic eq. and their zeroes are
alpha + beta = -b/a ,
& alpha × beta=c/a.
as ratio of zeroes is 1:1 means both zeroes of given quad. eq. are equal.
i.e., alpha=beta
now from eq. coefficient we get
a=a , b=1& c=1 .
clearly, we have
2alpha=-1/a -(1)& (alpha)^2 =1/a-(2)
adding (1)&(2) we get ,
(alpha)^2 +2alpha= 0
i.e. alpha (alpha+2)=0
i.e. alpha=0 or alpha=-2
but ,alpha=0 is not possible.
thus, alpha=-2
putting the value of alpha in (1) we get:
a=1/4
i hope it helps you.
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