Question

this are in pair 2x+3y=8; 4x+6y=k solve by substituting method

Answer 1

2x+3y=8
4x+6y= k
8-3y/2=x, then subsitute in the next eq.... 4(8-3y/2)+6y=k
Then.. 32-12y/2+6y=k
Taking lcm 32-12y+12y/2=k
2k=32
K=16