this have on us? If a=i+2j+3ť and b=2î +3j+5ť, then find angle between a vector and b vector
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Answer:
Given :
A
=
i
^
+2
j
^
−
k
^
B
=−
i
^
+
j
^
−2
k
^
A
.
B
=−1+2+2=3
∣
A
∣=
1
1
+2
2
+1
2
=
6
∣
B
∣=
1
1
+1
2
+2
2
=
6
⟹ cosθ=
∣
A
∣∣
B
∣
A
.
B
Or cosθ=
6
×
6
3
=
2
1
⟹ θ=60
o
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