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a + b + c + 2root ab - 2root bc - 2root ca
=(root a + root b - root c)^2
= factors = (root a + root b - root c) (root a + root b - root c)
( as per the identity (a+b-c)^2 = a^2 + b^2 - c^2 + 2ab - 2bc - 2ca)
=(root a + root b - root c)^2
= factors = (root a + root b - root c) (root a + root b - root c)
( as per the identity (a+b-c)^2 = a^2 + b^2 - c^2 + 2ab - 2bc - 2ca)
ashi2203:
no this is to 100 percent wrong
the values are present are variables than how ur ans come as constant
this question is identity based
which one ??
okk....but I will try
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