Question

This is a conic section. The standard form is (x - h)squared + (y - k)squared = (r)squared.
Example: In standard form, (x - h)2 + (y - k)2 = r2, h and k are the x- and y-coordinates of the center of the circle and r is the radius. If a circle has a center at (2, -3) and a radius of 6, then (h, k) = (2, -3) and r = 6. Substitute these values into the equation: (x - 2)2 + (y + 3)2 = 36.

Answer 1

Answer:

x^2+y^2-4x+6y-23=0

Step-by-step explanation:

(x-2)^2+(y+3)^2=36

x^2+4-4x+y^2+9+6y=36

x^2+y^2-4x+6y=23

Answer 2

Answer: Equation of a circle

Step-by-step explanation:

In standard form, (x - h)2 + (y - k)2 = r2, h and k are the x- and y-coordinates of the center of the circle and r is the radius. If a circle has a center at (2, -3) and a radius of 6, then (h, k) = (2, -3) and r = 6.

This is a conic section. The standard form is (x - h)squared + (y - k)squared = (r)squared. Therefore, it results to be an Equation of a Circle.