Question

this is even or odd​

Answer 1

Answer:

$f(x) = ln(x + \sqrt{1 + {x}^{2} } )$

$f( - x) = ln( - x + \sqrt{1 + { (- x)}^{2} } )$

$ln \: (x + \sqrt{1 + {x}^{2} } ) = sinhx$

$f(x) = sinhx$

$f( - x) = sinh( - x)$

$f( - x) = - sinhx$

$f(x) = - f(x)$

$therefore \: it \: is \: an \: even \: function$

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