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let angles of triangle are 2x,3x and 4x
sum of all angle of triangle is 180
therefore
2x+3x+4x=180
9x=180
x=20
hence
1st angle is 40
2nd is 60
3rd is 80
let angles of triangle are 2x,3x and 4x
sum of all angle of triangle is 180
therefore
2x+3x+4x=180
9x=180
x=20
hence
1st angle is 40
2nd is 60
3rd is 80
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1. angles of a triangle are in the ratio 2:3:4.....
so let X be the common multiple of this ratio .......
so the smallest angle is of 2x
second 3x
and 3rd 4x.....
by the property of a triangle.....
sum of measures of all angles in the triangle is 180° ......
so 2x+3x+4x= 180°......
so 9x= 180°.....
X= 180/9
X= 20°.....
so the 1st angle is 2x= 2*20=40
second angle =3*20=60
third angle=3*20=80........
so the angles are 40,60,80 ...
I hope it will help you......☺
so let X be the common multiple of this ratio .......
so the smallest angle is of 2x
second 3x
and 3rd 4x.....
by the property of a triangle.....
sum of measures of all angles in the triangle is 180° ......
so 2x+3x+4x= 180°......
so 9x= 180°.....
X= 180/9
X= 20°.....
so the 1st angle is 2x= 2*20=40
second angle =3*20=60
third angle=3*20=80........
so the angles are 40,60,80 ...
I hope it will help you......☺
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