Question

( this is MCQ) One of the roots of equation x2 +mx-5=0 is 2:find m.
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Answer 1

Answer:

Substituting x=2 in the equation, we get,

$\quad \bold \red{2 ^ { 2 } +m(2)-5=0}$

$\quad \bold \red{4+m\times 2-5=0 }$

$\quad \bold \red{-1+m\times 2=0 }$

$\quad \bold \red{m\times 2=1 }$

$\quad \displaystyle\bold \green{m = \frac{1}{2}}$