Question

This is my doubt, I want all the answers of u give I will mark u brainliest ​

Answer 1

Answer:

$\huge \underline \mathfrak\color{red} {Answer↓}$

i) 60m²

ii) 74m²

iii) 44m²

iv) 5.76m²

Step-by-step explanation:

In each of the figures from i to iii, we need to find the total area first.

i) Since, length and breadth are same, we consider it as a square (though it may not look like one).

$side \: of \: the \: square = 16m$

$\therefore \: area \: of \: the \: square = 16m \times 16m \\ = 256 {m}^{2}$

Now, there are 4 unshaded square with 7m as its side.

$area \: of \: the \: unshaded \: squares = (7m \times 7m) \times 4$

$= 49m ^{2} \times 4$

$= 196 {m}^{2}$

So, the area of the unshaded part is 196m²

$area \: of \: the \: shaded \: part = (256 - 196) {m}^{2}$

$= 60 {m}^{2}$

Therefore, the area of the shaded part is 60m².

ii) Here,

length = 14m

breadth = 7m

Therefore, it is a rectangle (though it may not look like one)

$area \: of \: the \: rectangle = 14m \times 7m \\ = 98 {m}^{2}$

There are 4 smaller squares with 2m as its side and a rectangle with 4m length and 2m breadth.

$area \: of \: unshaded \: parts = (2m \times 2m) \times 4 + (4m \times 2m)$

$= 4 {m}^{2} \times 4 + 8 {m}^{2}$

$= 16m ^{2} + 8m ^{2}$

$= 24 {m}^{2}$

$\therefore \: area \: of \: the \: shaded \: part =( 98 - 24) {m}^{2}$

$= 74 {m}^{2}$

iii)

$area \: of \: the \: rectangle = 12m \times 6m \\ = 72 {m}^{2}$

$area \: of \: the \: unshaded \: part = (12 - 3 - 2)m \times 4m$

$= 7m \times 4m$

$= 28 {m}^{2}$

$\therefore \: area \: of \: the \: shaded \: part = (72 - 28) {m}^{2}$

$44 {m}^{2}$

iv) In these figure, we need to find the area of all the rectangles separately then add them.

$first \: square = 0.6m \times 0.6m \\ = 0.36m ^{2}$

$first \: rectangle =( 0.6 + 0.6 + 0.6) m \times 0.6m$

$= 1.8m \times 0.6m$

$= 1.08 {m}^{2}$

$second \: rectangle =( 1.8 + 0.6 + 0.6)m \times 0.6m$

$= 3 m\times0.6m$

$= 1.8 {m}^{2}$

$third \: rectangle =( 3 + 0.6 + 0.6)m \times 0.6m$

$= 4.2 m\times 0.6m$

$= 2.52 {m}^{2}$

Now, we need to add all the areas.

$(0.36 + 1.08 + 1.8 + 2.52)m ^{2}$

$= 5.76 {m}^{2}$